A person is standing at the edge of a cliff and throws a stone up with...

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A person is standing at the edge of a cliff and throws a stone up with initial speed v = 7.03 m/s at an angle 0 = 47.4 to the horizon. The height of the cliff is h = 24.1 m above the ground. Air resistance can be ignored. Part 1) What is the maximum height the stone reaches above the ground? Take the ground to be at the bottom of the cliff; you are calculating the height of the stone from the bottom of the cliff. H = Part 2) What is the stone's time of flight? t = Part 3) S m What is the horizontal distance from the person where the stone hits the ground? x = m A person is standing at the edge of a cliff and throws a stone up with initial speed v = 7.03 m/s at an angle 0 = 47.4 to the horizon. The height of the cliff is h = 24.1 m above the ground. Air resistance can be ignored. Part 1) What is the maximum height the stone reaches above the ground? Take the ground to be at the bottom of the cliff; you are calculating the height of the stone from the bottom of the cliff. H = Part 2) What is the stone's time of flight? t = Part 3) S m What is the horizontal distance from the person where the stone hits the ground? x = m

Answer rating: 100% (QA)

To solve the problem we can break down the initial velocity into its horizontal and vertical compone... View the full answer