A plate 2-inch wide (2W) and 0.1-inch thick, is subjected to a constant amplitude stress varying...

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A plate 2-inch wide (2W) and 0.1-inch thick, is subjected to a constant amplitude stress varying between 40 ksi and 5 ksi. The plate contains a small crack of length a = 0.20-inch emanating from one of the free edges as shown. For the material, the Paris constants are C = 2.26 x 10-11 and m = 4 when AK is in ksi Vin and da/dN is in inch/cycle. By integrating the Paris equation, determine the number cycles for the crack to grow from 0.20 inch to 0.4 inch. If you choose to integrate numerically, take the integration step size Aa 0.05 inch. For this crack configuration and loading the stress intensity factor (SIF) K, is given by ()=1.120.231+10.55a 21.72 +30.39 a=a/2W. 2 in a A plate 2-inch wide (2W) and 0.1-inch thick, is subjected to a constant amplitude stress varying between 40 ksi and 5 ksi. The plate contains a small crack of length a = 0.20-inch emanating from one of the free edges as shown. For the material, the Paris constants are C = 2.26 x 10-11 and m = 4 when AK is in ksi Vin and da/dN is in inch/cycle. By integrating the Paris equation, determine the number cycles for the crack to grow from 0.20 inch to 0.4 inch. If you choose to integrate numerically, take the integration step size Aa 0.05 inch. For this crack configuration and loading the stress intensity factor (SIF) K, is given by ()=1.120.231+10.55a 21.72 +30.39 a=a/2W. 2 in a