A rod made of the material with the coefficient of linear expansion a = 0.02 (1/C)...

Transcribed Image Text:

A rod made of the material with the coefficient of linear expansion a = 0.02 (1/°C) is heated from to= -25 °C to t₁ = 25 °C so it would expand from Lo to L₁, for a change in length AL₁ = L₁ - Lo. Then the rod is heated from t₁ = 25 °C to t₂ = = 75 °C so it would expand from L₁ to L₂, for a change in length AL2 = L2-L₁. Calculate the ratio between AL2 and AL₁. A numerical value is required for credit. SHOW YOUR WORK. A rod made of the material with the coefficient of linear expansion a = 0.02 (1/°C) is heated from to= -25 °C to t₁ = 25 °C so it would expand from Lo to L₁, for a change in length AL₁ = L₁ - Lo. Then the rod is heated from t₁ = 25 °C to t₂ = = 75 °C so it would expand from L₁ to L₂, for a change in length AL2 = L2-L₁. Calculate the ratio between AL2 and AL₁. A numerical value is required for credit. SHOW YOUR WORK.

Answer rating: 100% (QA)

To calculate the ratio between L2 and L1 we can use the formula for linear expansion ... View the full answer