a) Series: 0 (-1 ) (-(2)^n/n)*x^n Incorrect. Tries 8/8 Previous Tries b) First four nonzero terms:...

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a) Series: 0 (-1 )" (-(2)^n/n)*x^n Incorrect. Tries 8/8 Previous Tries b) First four nonzero terms: -2x-2x^2-(8/3)(x^3)-4x^4 c) Within the interval of convergence: -1/2 < x < 1/2 Submit Answer Incorrect. Tries 1/8 Previous Tries g(x) = ln (12x) a) Series: 01 ( 1 Submit Answer =1 )" 2*-4^n*x^n Incorrect. Tries 1/8 Previous Tries b) First four nonzero terms: c) Within the interval of convergence: Submit Answer Tries 0/8 a) Series: 0 ( )n Submit Answer Tries 0/8 b) First four nonzero terms: x c) Within the interval of convergence: x Submit Answer Tries 0/8 g(x): = 1 (1 + 4x) 9 f(x) 2+x X g(x) = arctan a) Series: 0 (-1 |)" (1/sqrt(2))(1/2)^n*x^(2n) n=0 Submit Answer Incorrect. Tries 4/8 Previous Tries b) First four nonzero terms: sqrt(2)*(x/2-x^3/(2^2*3)+x^5/(2^3*5)-x^7/(2^4*7)) c) Within the interval of convergence: -sqrt(2) a) Determine the series of the given function. In the first box after the summation symbol, type in -1 or 1 indicating whether the series is alternating or not. b) Write out the sum of the first four nonzero terms of the series representing this function. c) Determine the interval of convergence. The outside boxes require the endpoints and the inside boxes require the symbol < or Give the Taylor series about x = 0 representing the function f(x) = ex Note that n! is entered as factorial(n). In the first box given, enter a 1 or a -1 indicating whether the series is alternating or not. e* = 0 ( 1 ) x^n/factorial(n) n=0 You are correct. Previous Tries Your receipt no. is 153-3822 Give the series for the following evaluations. Also give the first five terms of the series. e5 = n=0 1 )n 5/factorial(n) First five terms of series: 1+5/factorial(1)+5^2/factorial(2)+5^3/factorial (3)+5^4/factc Incorrect. Tries 8/8 Previous Tries e-1 = n=0 )n First five terms of series: Submit Answer V = Tries 0/8 n First five terms of series: Submit Answer Tries 0/8 a) Series: 0 (-1 )" (-(2)^n/n)*x^n Incorrect. Tries 8/8 Previous Tries b) First four nonzero terms: -2x-2x^2-(8/3)(x^3)-4x^4 c) Within the interval of convergence: -1/2 < x < 1/2 Submit Answer Incorrect. Tries 1/8 Previous Tries g(x) = ln (12x) a) Series: 01 ( 1 Submit Answer =1 )" 2*-4^n*x^n Incorrect. Tries 1/8 Previous Tries b) First four nonzero terms: c) Within the interval of convergence: Submit Answer Tries 0/8 a) Series: 0 ( )n Submit Answer Tries 0/8 b) First four nonzero terms: x c) Within the interval of convergence: x Submit Answer Tries 0/8 g(x): = 1 (1 + 4x) 9 f(x) 2+x X g(x) = arctan a) Series: 0 (-1 |)" (1/sqrt(2))(1/2)^n*x^(2n) n=0 Submit Answer Incorrect. Tries 4/8 Previous Tries b) First four nonzero terms: sqrt(2)*(x/2-x^3/(2^2*3)+x^5/(2^3*5)-x^7/(2^4*7)) c) Within the interval of convergence: -sqrt(2) a) Determine the series of the given function. In the first box after the summation symbol, type in -1 or 1 indicating whether the series is alternating or not. b) Write out the sum of the first four nonzero terms of the series representing this function. c) Determine the interval of convergence. The outside boxes require the endpoints and the inside boxes require the symbol < or Give the Taylor series about x = 0 representing the function f(x) = ex Note that n! is entered as factorial(n). In the first box given, enter a 1 or a -1 indicating whether the series is alternating or not. e* = 0 ( 1 ) x^n/factorial(n) n=0 You are correct. Previous Tries Your receipt no. is 153-3822 Give the series for the following evaluations. Also give the first five terms of the series. e5 = n=0 1 )n 5/factorial(n) First five terms of series: 1+5/factorial(1)+5^2/factorial(2)+5^3/factorial (3)+5^4/factc Incorrect. Tries 8/8 Previous Tries e-1 = n=0 )n First five terms of series: Submit Answer V = Tries 0/8 n First five terms of series: Submit Answer Tries 0/8