A stone is thrown vertically upwards, from the ground, with a velocity of 45 m/s. After...

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A stone is thrown vertically upwards, from the ground, with a velocity of 45 m/s. After 1 seconds, second stone is thrown vertically upwards from the same place. If both the stone strike the ground at the same time, find the velocity, with which the second stone was thrown upwards. Take g=9.81 m/s². (Enter only the values in the boxes by referring the units given in bracket) (1) Time taken by the first stone to reach maximum height (unit is in seconds) (2) The maximum height reached by the first stone (unit is in m) = (3) The total time taken by first stone is (unit in seconds) = (4 Marks) (4) The time taken by the second stone to reach maximum height is (unit is in seconds) = (5) The initial velocity of the second stone is (unit is in m/s) = A stone is thrown vertically upwards, from the ground, with a velocity of 45 m/s. After 1 seconds, second stone is thrown vertically upwards from the same place. If both the stone strike the ground at the same time, find the velocity, with which the second stone was thrown upwards. Take g=9.81 m/s². (Enter only the values in the boxes by referring the units given in bracket) (1) Time taken by the first stone to reach maximum height (unit is in seconds) (2) The maximum height reached by the first stone (unit is in m) = (3) The total time taken by first stone is (unit in seconds) = (4 Marks) (4) The time taken by the second stone to reach maximum height is (unit is in seconds) = (5) The initial velocity of the second stone is (unit is in m/s) =

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To solve these problems we will use the kinematic equations for uniformly accelerated motion considering the acceleration due to gravity g 981 ms poin... View the full answer