A. The activation energy of a certain reaction is 36.8 kJ/mol at28 degrees Celsius the rate constant
Fantastic news! We've Found the answer you've been seeking!
Question:
A. The activation energy of a certain reaction is 36.8 kJ/mol at28 degrees Celsius the rate constant is 0.0190s^-1 at what temperature in degrees Celsius would this reaction go twice as fast?
B. Given that the initial rate constant is 0.0190s^-1 at aninitial temperature of 28 degrees celsius what would the rateconstant be at a temperature of 150 degrees celsius for the same reaction described in part A?
Related Book For
Posted Date: