A thermocouple produces an e.m.f. in mV according to the temperature difference between the sensor tip...

 

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A thermocouple produces an e.m.f. in mV according to the temperature difference between the sensor tip 0 and the gauge head 02 such that e = = a(0-0) + B(0 - 0). x= 3.5 x 10- (mV/K), = 8.2 x 10-6 (mV/K) The gauge head is at 20C. The mV output is 10 mV. Calculate the temperature at the sensor. A thermocouple produces an e.m.f. in mV according to the temperature difference between the sensor tip 0 and the gauge head 02 such that e = = a(0-0) + B(0 - 0). x= 3.5 x 10- (mV/K), = 8.2 x 10-6 (mV/K) The gauge head is at 20C. The mV output is 10 mV. Calculate the temperature at the sensor.

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Given e 10 mV alpha 35 102 mV K beta 82 106 mV K2 theta2 20 deg C The eq... View the full answer