(a) Use the conversion factor 10 psi = 0.06895 MPa to convert 4360 psi to MPa. (Note: You must show step by step calculations to get a full mark.) (b) Use the conversion factors 1ft = 1728 inand 1 ft?=0.0283168 m to convert 125875 in to m. (Note: You must show step by step calculations to get a full mark.) (c) A sample coarse aggregate from the field weighs 22.6 kg and has a total moisture content of 6.5%. If its volume is 0.01412 m (i) What is the unit weight of the aggregate at this moisture content? (ii) What is the oven-dry unit weight? (d) A sample of fine aggregate weighs 548 g when in SSD condition, and 533 g when sample was oven dried. A test container weighs 655 g when filled with water, and 988 g when filled with fine aggregate and water. Calculate the bulk specific gravity and the percentage of absorption. (e) O A sample of coarse aggregate from the field yielded the following data: Oven dry rodded unit weight (DRUW) = 1580 kg/m Bulk Specific gravity (SG00) = 2.64 Moisture content = 3.0% o Absorption = 1.0% (i) What is the weight of 20 m of aggregate from the field? (ii) What is the weight of 20 m of aggregate at SSD condition? (iii) What is the percent voids in 1 m' of aggregate?

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a To convert 4360 psi to MPa using the conversion factor 10 psi 006895 MPa 4360 psi 006895 MPa 10 ps... View the full answer