A V-belt from a 10-in-diameter sheave that rotates at 1800 rpm, up to a 36 in. diameter flat pulley. Distance wheelbase is 40" and the throat angle is 40o . friction coefficient between the belt and the grooved pulley is 0.2 and with the flat pulley it is also 0.2. The cross section of the purlins is a trapezoid with parallel sides of 1.5" and 0.75", with a height between them of 1”. The weight of this strap is 0.04 lbf/in3 , and the maximum allowable tension in each strap is 200 lbf. 

Determine: 

a) How many straps will be they need. 

b) The Torque applied in the transmission, 

c) The Power Transmitted. Note: Consider locating the center of gravity of the belt cross-section, in order to correct the actual pulley diameter as the belt on the sheave lies out a bit).

Answer rating: 100% (QA)

To calculate the number of straps center of gravity of the belt cross section actual pulley diameters torque and power transmitted we can use the following steps a Number of straps The number of straps is calculated as follows Number of straps Actual flat pulley diameter ... View the full answer