1. A channel h is defined by its impulse response with h[0] = 0.5, h[1] =...

 

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1. A channel h is defined by its impulse response with h[0] = 0.5, h[1] = j/2, and h[2] = 0.4exp(jn/5). Use Matlab to calculate the Least Squares Equalizer of length Lf = 5. The LS Equalizer is given by fLS,na = (H*H)-¹H*ena squared error corresponding to a delay n_d is given by J[na] = e(I-H(H*H)-¹H*)ena a. Write down the channel convolution matrix H formed from the vector channel defined by h. b. Generate a plot of the squared error as a function of delay parameter. c. What is the delay corresponding to the minimum squared error min /[na]. d. Write down the fLs,nd using the delay value calculated in c. 1. A channel h is defined by its impulse response with h[0] = 0.5, h[1] = j/2, and h[2] = 0.4exp(jn/5). Use Matlab to calculate the Least Squares Equalizer of length Lf = 5. The LS Equalizer is given by fLS,na = (H*H)-¹H*ena squared error corresponding to a delay n_d is given by J[na] = e(I-H(H*H)-¹H*)ena a. Write down the channel convolution matrix H formed from the vector channel defined by h. b. Generate a plot of the squared error as a function of delay parameter. c. What is the delay corresponding to the minimum squared error min /[na]. d. Write down the fLs,nd using the delay value calculated in c.

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a H 0 5 j 2 0 4 exp j 5 0 0 0 0 5 j 2 0 4 exp j 5 0 0 0 0 5 j 2 0 4 exp j 5 0 0 0 0 5 j 2 0 0 ... View the full answer