10 The operation point of the transistor BFR 182 is UCE = 5 V and Ic...
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10 The operation point of the transistor BFR 182 is UCE = 5 V and Ic = 9 mA. At a frequency of 5 GHz it is described by the following set of y-parameters: 44.61 exp(-j8.44°) 33.06 exp(-j141.8⁰) (Y) = ( 88.0 exp(-j172.8°) 68.76 exp(j40.06⁰) mS a) Calculate the center and radius of the stability circle in the load plane. b) A resistor is connected in parallel to the output of the transistor. Which value do you have to choose to reach stability? 10 The operation point of the transistor BFR 182 is UCE = 5 V and Ic = 9 mA. At a frequency of 5 GHz it is described by the following set of y-parameters: 44.61 exp(-j8.44°) 33.06 exp(-j141.8⁰) (Y) = ( 88.0 exp(-j172.8°) 68.76 exp(j40.06⁰) mS a) Calculate the center and radius of the stability circle in the load plane. b) A resistor is connected in parallel to the output of the transistor. Which value do you have to choose to reach stability?
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a The center and radius of the stability circle can be determined using the following equation ... View the full answer
Related Book For
Fundamentals of Momentum, Heat and Mass Transfer
ISBN: 978-1118947463
6th edition
Authors: James Welty, Gregory L. Rorrer, David G. Foster
Posted Date:
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