10 of 15 In the reaction MnO4 + 8H* +5eMn+ + 4H0, the manganese in 3.95...

 

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10 of 15 In the reaction MnO4 + 8H* +5eMn²+ + 4H₂0, the manganese in 3.95 grams of KMnO4 is reduced to Mn²+. How many coulombs of charge must have been transferred to the permanganate ion? Hint: 1. Calculate number of moles; 2. Q = nF 3. Answer: 1.20 x 104 C 11 of 15 Calculate E for the reaction MnO4 + 8H* + 5Fe²+Mn²+ + 4H₂O + 5Fe³+. Hint: 1. Write the half-cells' reactions and then use Eº cell/Mn04 = 1.507 V; EO cell/Fe2+ = 0.771V 2. Calculate the overall potential 3. Answer: + 0.736 V 10 of 15 In the reaction MnO4 + 8H* +5eMn²+ + 4H₂0, the manganese in 3.95 grams of KMnO4 is reduced to Mn²+. How many coulombs of charge must have been transferred to the permanganate ion? Hint: 1. Calculate number of moles; 2. Q = nF 3. Answer: 1.20 x 104 C 11 of 15 Calculate E for the reaction MnO4 + 8H* + 5Fe²+Mn²+ + 4H₂O + 5Fe³+. Hint: 1. Write the half-cells' reactions and then use Eº cell/Mn04 = 1.507 V; EO cell/Fe2+ = 0.771V 2. Calculate the overall potential 3. Answer: + 0.736 V

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10 1 Mass of KMnO4 395 g Molar mass of KMnO4 158 gmol Moles of KMnO4 mas... View the full answer