An 10-kg block starts sliding with a velocity of 10 m/s down a inclined plane with...

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An 10-kg block starts sliding with a velocity of 10 m/s down a inclined plane with an angle of inclination of 30 degrees, as shown in the figure below. The highest point of the incline is at a vertical height of h. At point M, which is at a vertical height of h/3, the block moving with a velocity of 6 m/s. The frictional force acting on the block is 100 N. Calculate the height h in meters. Round to the first decimal. g = 10 m/s. Attach your work for partial credit. M 1/3 h An 10-kg block starts sliding with a velocity of 10 m/s down a inclined plane with an angle of inclination of 30 degrees, as shown in the figure below. The highest point of the incline is at a vertical height of h. At point M, which is at a vertical height of h/3, the block moving with a velocity of 6 m/s. The frictional force acting on the block is 100 N. Calculate the height h in meters. Round to the first decimal. g = 10 m/s. Attach your work for partial credit. M 1/3 h

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To find the height h of the inclined plane we can use the principle of conservation of mechanical en... View the full answer