An electrolysis experiment was run for 19 minutes and 45 seconds at an average current of...

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An electrolysis experiment was run for 19 minutes and 45 seconds at an average current of 182 milliamps (mA). The mass lost by the copper anode was 0.0745 grams. (b) Calculate the number of coulombs transferred. (Remember: coulomb = amps x sec) (C) (d) Calculate the moles of copper lost from the anode. Based on the moles of copper lost determined in 1c, calculate the moles of electrons --> Cu2 (aq) + 2 e transferred. Remember, the reaction at the copper anode is: Cu(s) An electrolysis experiment was run for 19 minutes and 45 seconds at an average current of 182 milliamps (mA). The mass lost by the copper anode was 0.0745 grams. (b) Calculate the number of coulombs transferred. (Remember: coulomb = amps x sec) (C) (d) Calculate the moles of copper lost from the anode. Based on the moles of copper lost determined in 1c, calculate the moles of electrons --> Cu2 (aq) + 2 e transferred. Remember, the reaction at the copper anode is: Cu(s)

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2 No of Coulombs transfered Current in Amperes xhmen seens ... View the full answer