An elevator, initially at rest, starts moving upwards at constant acceleration and eventually reaches speed 8.24...

 

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An elevator, initially at rest, starts moving upwards at constant acceleration and eventually reaches speed 8.24 m/s at time t= 6.26 s. It travels at constant speed until time t= 24.36 s. The elevator then begins to slow down with constant deceleration, and at time t-34.14 s stops at the destination floor. Define upward direction as positive. (a) What is the acceleration of the elevator in the time period between 0 and 6.26 s? 1.32 m/s (b) What is the acceleration of the elevator in the time period between 6.26 and 24.36 s? 0.269 m/s (c) What is the acceleration of the elevator in the time period between 24.36 and 34.14 s? m/s (d) What is the height of the destination floor above the initial position in m? Numb m An elevator, initially at rest, starts moving upwards at constant acceleration and eventually reaches speed 8.24 m/s at time t= 6.26 s. It travels at constant speed until time t= 24.36 s. The elevator then begins to slow down with constant deceleration, and at time t-34.14 s stops at the destination floor. Define upward direction as positive. (a) What is the acceleration of the elevator in the time period between 0 and 6.26 s? 1.32 m/s (b) What is the acceleration of the elevator in the time period between 6.26 and 24.36 s? 0.269 m/s (c) What is the acceleration of the elevator in the time period between 24.36 and 34.14 s? m/s (d) What is the height of the destination floor above the initial position in m? Numb m

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Lets solve each part of the problem step by step a Acceleration of the elevator in the time period b... View the full answer