An FCC metal possesses nitrogen (N) interstitial species. In this metal, the N has an associated diffusion coefficient of 2.5610⁷ cm²/s at 600 C. Assume the lattice parameter of this FCC metal is 0.50 nm (5 10⁸ cm).

A.) Assume that the nitrogen diffuses between FCC octahedral sites in this crystal. Determine the jump distance _NN (where NN stands for nearest neighbor) in this system. At 600 C, what fraction of attempted jumps are successful? Remember that the lattice vibration frequency is = 10¹³s ¹ .

B.) In this system, the diffusion coefficient is 1.12 10¹⁰cm²/s at 300 C. Find both the activation energy and the pre-exponential factor for this interstitial diffusion process.

C.) Calculate the random walk displacement and total distance traveled by an interstitial N in this FCC metal at 600 C in on second.

D.) The equation for the random walk displacement r_Random = (t) seems to suggest that direct diffusion via the next-nearest-neighbor (NNN) octahedral site (positioned at a distance of a), would increase the mean random walk displacement by a factor of a/_NN. Does this make sense? If so, why? If not, how can you reconcile this odd apparent behavior - that random walk jumps between next-nearest neighbors would yield larger random walk displacements than jumps between nearest neighbors?