An object of height 3 cm is placed at 22 cm in front of a diverging...
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An object of height 3 cm is placed at 22 cm in front of a diverging lens of focal length, f = 16 cm. Behind the diverging lens, there is a converging lens of focal length, f = 16 cm. The distance between the lenses is 7 cm. In the next few steps, you will find the location and size of the final image. Hint = a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is dil= cm. (Use the sign to indicate which side the image is on; positive sign means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is diz cm. (Use the sign to indicate which side the image is on.) = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is cm. (Use the sign to indicate whether the image is upright hil = (positive) or inverted (negative).) d. How large is the final image formed by the second converging lens? Final image height is h42 cm. (Use the sign to indicate whether the image is upright or inverted.) An object of height 3 cm is placed at 22 cm in front of a diverging lens of focal length, f = 16 cm. Behind the diverging lens, there is a converging lens of focal length, f = 16 cm. The distance between the lenses is 7 cm. In the next few steps, you will find the location and size of the final image. Hint = a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is dil= cm. (Use the sign to indicate which side the image is on; positive sign means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is diz cm. (Use the sign to indicate which side the image is on.) = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is cm. (Use the sign to indicate whether the image is upright hil = (positive) or inverted (negative).) d. How large is the final image formed by the second converging lens? Final image height is h42 cm. (Use the sign to indicate whether the image is upright or inverted.)
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To solve this problem we can use the lens formula for both the diverging and converging lenses 1 For ... View the full answer
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Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
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