At 1700 °C, the equilibrium constant, Kc, for the following reaction is 4.10 × 10–4.

N2(g)+O2(g) ⇌ 2NO(g)

What percentage of O2 will react to form NO if 0.447 mol of N2and 0.447 mol of O2 are added to a 0.619-L  container and allowed to come to equilbrium at 1700 °C?

 

Answer rating: 100% (QA)

Initial moles are Moles of N 0447 mol Moles of O 0447 mol Total volume 0619 L N moles 0447 ... View the full answer