At a bowling alley, two players each score a spare when their bowling balls make head-on, approximately elastic collisions at the same speed with identical pins. After the collisions, the pin hit by ball A moves much more quickly than the pin hit by ball B.

(A response, answer only, without mathematical justification will receive only 15% credit, if correct. Partial credit can potentially be given for an incorrect answer only if there is mathematical evidence for the response.)

Momentum of ball A (m_AV_before) before hitting the pin = momentum of pin (m_pinv_pinA) after the collision Momentum of ball B (m_B V_before) before hitting the pin = momentum of pin (m_pinv_pinB) after the collision

(Note V_before is the same for ball A and ball B)

Comparing the Conservation of Momentum information determine which ball has more mass, ball A or ball B?

Answer rating: 100% (QA)

Based on the conservation of momentum principle which states that the ... View the full answer