Balance the following reaction:
C9H20(g) + O2(g) = CO2(g) + H2O(g).
If you initially have 130 g of hydrocarbon 85 g of oxygen according to the previous reaction.
a) What is the limiting reactant?
b) How many grams of CO2 are formed? And how many moles of CO2 do those grams represent?
c) How many liters of water are formed?
d) How much of the excess reagent was left over?

Answer rating: 100% (QA)

IBalanced equation C9H2O 9 O2 9 CO2 H2O a limiting reactant is oxygen b 40829807223095617g of CO2 a... View the full answer