Below are ten functions. Find the first derivative of each. Space is provided. Use good dark...
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Below are ten functions. Find the first derivative of each. Space is provided. Use good dark ink if you are returning this by a scanned version. All of the derivatives can be found by using combinations of the constant rule, power function rule and sum-difference rule. Do not use the product rule. It is not needed. The degree of difficulty (more or less) increases from (a) to (j). Be sure to show intermediate work. Five points are awarded for correctly developed derivatives. There is no partial credit, because an incorrect derivative is useless. For example, the first derivative of the function: Y = (2x + 3) is: a) Y = 60 8Q +6Q-5 dx/dQ= The above is satisfactory, although this can be simplified to: dY dX please do not simplify your answer. This also avoids algebraic mistakes on your part. HINT: For (i) and also for (j), multiply the two parts together first, then find the derivative of the product. b) Y = 10 +4X4 - 3X dx/dx = c) R = 2S-5S-3 + 4S-10 dR/ds= d) T = 3X-2X+5X-7 dT/dx = dy dX e) W=3V4-45+2V/ dW/dv= = 2(2X + 3)(2) = 8X +12 f) U = 5V +3V 5V +15 du dv= g) Q =p/2-p-3/2 + P dQ/dp = h) T = US14 +2U5/2 - 304/5 dT/dU = i) Z = 3W (2+3W) dz/dw= j) Z = 4x/2 (2X-3X) dz/dx= Below are ten functions. Find the first derivative of each. Space is provided. Use good dark ink if you are returning this by a scanned version. All of the derivatives can be found by using combinations of the constant rule, power function rule and sum-difference rule. Do not use the product rule. It is not needed. The degree of difficulty (more or less) increases from (a) to (j). Be sure to show intermediate work. Five points are awarded for correctly developed derivatives. There is no partial credit, because an incorrect derivative is useless. For example, the first derivative of the function: Y = (2x + 3) is: a) Y = 60 8Q +6Q-5 dx/dQ= The above is satisfactory, although this can be simplified to: dY dX please do not simplify your answer. This also avoids algebraic mistakes on your part. HINT: For (i) and also for (j), multiply the two parts together first, then find the derivative of the product. b) Y = 10 +4X4 - 3X dx/dx = c) R = 2S-5S-3 + 4S-10 dR/ds= d) T = 3X-2X+5X-7 dT/dx = dy dX e) W=3V4-45+2V/ dW/dv= = 2(2X + 3)(2) = 8X +12 f) U = 5V +3V 5V +15 du dv= g) Q =p/2-p-3/2 + P dQ/dp = h) T = US14 +2U5/2 - 304/5 dT/dU = i) Z = 3W (2+3W) dz/dw= j) Z = 4x/2 (2X-3X) dz/dx=
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a Y 603802 605 dYdQ 0 b Y 10 4X4 3X2 dYdX 16X3 6X c R2S 5S 3 4S2 10 dR... View the full answer
Related Book For
Modeling the Dynamics of Life Calculus and Probability for Life Scientists
ISBN: 978-0840064189
3rd edition
Authors: Frederick R. Adler
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