) Briefly explain what the following function is doing: fun foo 11 12 = foldl (fn...
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) Briefly explain what the following function is doing: fun foo 11 12 = foldl (fn (hd, acc) => if (exists 12 hd) then acc else hd ::acc) [] 11 foo: 'a list -> 'a list -> 'a list assuming that function exists is defined as fun exists [] n = false I exists (x:xs) n = if n = x then true else exists xs n For example, what is the result of foo ["a","b", "c"] ["b", "c"]? ) Briefly explain what the following function is doing: fun foo 11 12 = foldl (fn (hd, acc) => if (exists 12 hd) then acc else hd ::acc) [] 11 foo: 'a list -> 'a list -> 'a list assuming that function exists is defined as fun exists [] n = false I exists (x:xs) n = if n = x then true else exists xs n For example, what is the result of foo ["a","b", "c"] ["b", "c"]?
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The function foo performs a left fold on a list using a function that returns the head of the list if the element 12 is not in the head and the accumu... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
Posted Date:
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