Calculate the maximum numbers of moles and grams of H 2 S that can form when 147 3 g of aluminum sulfide reacts with 143 0 g of water Al 2 S 3 H 2 O Al(OH) 3 H 2 S unbalanced mol H 2 S g H 2 S What mass of the excess reactant remains g excess reactant ...

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Calculate the maximum numbers of moles and grams of H 2 S that can form when 147.3

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Question:

Calculate the maximum numbers of moles and grams of H₂S that can form when 147.3 g of aluminum sulfide reacts with 143.0 g of water:

Al₂S₃ + H₂O → Al(OH)₃ + H₂S [unbalanced]

mol H₂S

g H₂S

What mass of the excess reactant remains?

g excess reactant