Chebyshev's inequality states that the probability of a deviation of a discrete random variable X with...

Transcribed Image Text:

Chebyshev's inequality states that the probability of a deviation of a discrete random variable X with expected value and variance Var(X) is given by P(|X- e) Var (X) where is any positive real number. Show that the probability of a deviation from the mean of more than k standard deviations is less than or equal to 1/k. Chebyshev's inequality states that the probability of a deviation of a discrete random variable X with expected value and variance Var(X) is given by P(|X- e) Var (X) where is any positive real number. Show that the probability of a deviation from the mean of more than k standard deviations is less than or equal to 1/k.

Answer rating: 100% (QA)

The detailed ... View the full answer