Classical Subnetting 200.35.1.0/24 Question 18 (1 point) Assume that you have been assigned the 200.35.1.0/24 network...

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Classical Subnetting 200.35.1.0/24 Question 18 (1 point) Assume that you have been assigned the 200.35.1.0/24 network block. You must address up to twenty (20) hosts on each subnet. Specify the minimum number of host bits that are required. (Hint: This is the number of host bits to "keep," not the number of subnet bits to "steal.") Given the minimum number of host bits necessary to address twenty (20) hosts, use the formula (2N - 2) to calculate the maximum number of hosts that can be addressed on each subnet. (Hint: "N" is the number of host bits that remain after subtracting the subnet bits.) Given the minimum number of host bits necessary to address twenty (20) hosts, use the formula (2¹) to calculate the maximum number of subnets that can be defined in 200.35.1.0/24. (Hint: "N" is the number of subnet bits, not host bits.) Express all subnets of 200.35.1.0/24 that you've created in both binary format and dotted decimal notation. Subnet #0: Binary Format= Subnet #1: Binary Format= Subnet #2: Binary Format= N A/ Dotted Decimal Notation = A Dotted Decimal Notation = A/ Dotted Decimal Notation = Subnet #3: Binary Format= Subnet #4: Binary Format= Subnet #5: Binary Format= Subnet #6: Binary Format= Subnet #7: Binary Format= N First IP Address: Binary Format= N A/ Dotted Decimal Notation = N A/ Dotted Decimal Notation = A Dotted Decimal Notation = Dotted Decimal Notation = Specify the IP addresses of each of the following hosts in Subnet #6 in both binary format and dotted decimal notation. A/ Dotted Decimal Notation = A Dotted Decimal Notation = Second IP Address: Binary Format= Third IP Address: Binary Format= Next to Last IP Address: Binary Format= Last IP Address: Binary Format= Binary Format= N Notation = N A Dotted Decimal Notation = Dotted Decimal Notation = A/ Dotted Decimal Notation = For Subnet #6, specify the IP broadcast address: A/ Dotted Decimal Notation = A/ Dotted Decimal Classical Subnetting 200.35.1.0/24 Question 18 (1 point) Assume that you have been assigned the 200.35.1.0/24 network block. You must address up to twenty (20) hosts on each subnet. Specify the minimum number of host bits that are required. (Hint: This is the number of host bits to "keep," not the number of subnet bits to "steal.") Given the minimum number of host bits necessary to address twenty (20) hosts, use the formula (2N - 2) to calculate the maximum number of hosts that can be addressed on each subnet. (Hint: "N" is the number of host bits that remain after subtracting the subnet bits.) Given the minimum number of host bits necessary to address twenty (20) hosts, use the formula (2¹) to calculate the maximum number of subnets that can be defined in 200.35.1.0/24. (Hint: "N" is the number of subnet bits, not host bits.) Express all subnets of 200.35.1.0/24 that you've created in both binary format and dotted decimal notation. Subnet #0: Binary Format= Subnet #1: Binary Format= Subnet #2: Binary Format= N A/ Dotted Decimal Notation = A Dotted Decimal Notation = A/ Dotted Decimal Notation = Subnet #3: Binary Format= Subnet #4: Binary Format= Subnet #5: Binary Format= Subnet #6: Binary Format= Subnet #7: Binary Format= N First IP Address: Binary Format= N A/ Dotted Decimal Notation = N A/ Dotted Decimal Notation = A Dotted Decimal Notation = Dotted Decimal Notation = Specify the IP addresses of each of the following hosts in Subnet #6 in both binary format and dotted decimal notation. A/ Dotted Decimal Notation = A Dotted Decimal Notation = Second IP Address: Binary Format= Third IP Address: Binary Format= Next to Last IP Address: Binary Format= Last IP Address: Binary Format= Binary Format= N Notation = N A Dotted Decimal Notation = Dotted Decimal Notation = A/ Dotted Decimal Notation = For Subnet #6, specify the IP broadcast address: A/ Dotted Decimal Notation = A/ Dotted Decimal

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