Consider acetic acid, CH 3 COOH, the active ingredient in vinegar. It is also responsible for the
Question:
Consider acetic acid, CH3COOH, the active ingredient in vinegar. It is also responsible for the sour taste of wine when wine gets exposed to air. Bacterial oxidation turns alcohol to acid.
C2H5OH(aq) + O2(g) —> CH3COOH(aq) + H2O(l)
The following data may be useful:
C2H5OH(aq): ΔHf° = -288.3 kJ/mol; S° = 148.5 J/mol•K
CH3COOH(aq): ΔHf° = -485.8 kJ/mol; S° = 178.7 J/mol•K
(a) Calculate ΔH° and ΔS° for this process.
(b) Is the reaction spontaneous at 25°C? At 4°C?
(c) The heat of vaporization for acetic acid is 24.3 kJ/mol. Its normal boiling point is 118.5°C. Calculate ΔS° for the reaction: CH3COOH(l) —> CH3COOH(g)
(d) What is the standard molar entropy for CH3COOH(g), taking S° for CH3COOH(l) to be 159.8 J/mol•K
(e) Calculate ΔG at 25°C for the formation of acetic acid from ethanol (see reaction above) when [CH3COOH] = 0.200 M, PO2 = 1.13 atm, and [C2H5OH] = 0.125 M.
(f) Calculate ΔG° for the ionization of acetic acid at 25°C (Ka = 1.8 x 10-5).