Consider the system shown in the single-line diagram of Figure (5.) Here, a 60-Hz synchronous generator...

 

Transcribed Image Text:

Consider the system shown in the single-line diagram of Figure (5.) Here, a 60-Hz synchronous generator whose transient reactance is 0.30 p.u. is connected to bus 1 through a transformer whose reactance is 0.10 p.u. Bus 1 is connected to the infinite bus labeled 2 through two parallel paths. The first path is transmission line (1-2) whose reactance is 0.2 p.u. The second path connects buses 1 and 2 via bus 3. Section 1-3 consists of two parallel lines whose reactances are 0.10 p.u. As indicated in the figure, the reactance of section 3-2 is 0.10 p.u. The generator delivers an active power of 1.8 p.u. to a 0.8 pf lagging load connected to the infinite bus (2.) The magnitude of the voltage at bus 2 is 1.0 p.u. a- Determine the value of the excitation voltage of the generator under these conditions. [5 points] b- Determine the equation of the electrical power delivered by the generator versus its power angle under the conditions of part (a). [3 points] c- Suppose that the magnitude of the voltage at bus 2 is 1.0 p.u and the generator's excitation voltage is set at E= 1.2. Suppose that the synchronous generator is initially operating in the steady state delivering an active power of 2.0 p.u., and that a three phase-to-ground bolted short circuit occurs at point F between breakers Be and Bg in one line of section 1-3. The fault is cleared by opening breakers B, and B, for 8=80°. Determine whether the system is stable or not under these conditions. [12 points] G XTR = 0.10 X 0.30 THE 80 Bm Ba 8 X130.10 B3 Be X, 20.06 X12 = 0.20 F 0 8g -0.04 8h Bb Bk X230.10 Vous = 1.0 Consider the system shown in the single-line diagram of Figure (5.) Here, a 60-Hz synchronous generator whose transient reactance is 0.30 p.u. is connected to bus 1 through a transformer whose reactance is 0.10 p.u. Bus 1 is connected to the infinite bus labeled 2 through two parallel paths. The first path is transmission line (1-2) whose reactance is 0.2 p.u. The second path connects buses 1 and 2 via bus 3. Section 1-3 consists of two parallel lines whose reactances are 0.10 p.u. As indicated in the figure, the reactance of section 3-2 is 0.10 p.u. The generator delivers an active power of 1.8 p.u. to a 0.8 pf lagging load connected to the infinite bus (2.) The magnitude of the voltage at bus 2 is 1.0 p.u. a- Determine the value of the excitation voltage of the generator under these conditions. [5 points] b- Determine the equation of the electrical power delivered by the generator versus its power angle under the conditions of part (a). [3 points] c- Suppose that the magnitude of the voltage at bus 2 is 1.0 p.u and the generator's excitation voltage is set at E= 1.2. Suppose that the synchronous generator is initially operating in the steady state delivering an active power of 2.0 p.u., and that a three phase-to-ground bolted short circuit occurs at point F between breakers Be and Bg in one line of section 1-3. The fault is cleared by opening breakers B, and B, for 8=80°. Determine whether the system is stable or not under these conditions. [12 points] G XTR = 0.10 X 0.30 THE 80 Bm Ba 8 X130.10 B3 Be X, 20.06 X12 = 0.20 F 0 8g -0.04 8h Bb Bk X230.10 Vous = 1.0