(2) = Iff'(x) = 2x-x x + 1 and (0) = -1, then 4.A 2.B 3.C...
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√(2) = Iff'(x) = 2x²-x x + 1 and (0) = -1, then 4.A 2.B 3.C 5.D -1.E √(2) = Iff'(x) = 2x²-x x + 1 and (0) = -1, then 4.A 2.B 3.C 5.D -1.E
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