d) A gas flows at the rate of 15 kmol/s at 298 K and 1 atm...

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d) A gas flows at the rate of 15 kmol/s at 298 K and 1 atm with a H,S content of 0.10 mol%. 95% of the H;S is to be removed by absorption with a pure liquid at 298 K. The design liquid flow rate will be 30% higher than the minimum. Under these conditions, the equilibrium line based on solute free basis is given by; 10X Y = (1– 9X) i) Calculate the operating flow rate of the liquid ii) the H,S concentration in the liquid leaving the absorber [8 marks] [4 marks] d) A gas flows at the rate of 15 kmol/s at 298 K and 1 atm with a H,S content of 0.10 mol%. 95% of the H;S is to be removed by absorption with a pure liquid at 298 K. The design liquid flow rate will be 30% higher than the minimum. Under these conditions, the equilibrium line based on solute free basis is given by; 10X Y = (1– 9X) i) Calculate the operating flow rate of the liquid ii) the H,S concentration in the liquid leaving the absorber [8 marks] [4 marks]