Using the volume of base at the equivalence point, its molarity, and the fact that you...
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Using the volume of base at the equivalence point, its molarity, and the fact that you used 25.00 mL of acid, calculate the concentration of the unknown acid and record this on the report sheet. D. Concentration of Unknown Acid Volume of unknown acid Average molarity of NaOH from above mL of NaOH at equivalence point Molarity of unknown acid Average molarity (show calculations) Trial 1 Trial 2 Standard deviation Laboratory Experim Trial 3 B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Mass of bottle + KHP Mass of bottle Mass of KHP used 4139 14.09g Final buret reading 19.55 Initial buret reading 22,10 mL of NaOH used 13.30 17.55 Molarity of NaOH 117 M 114 M Average molarity (show calculations and standard deviation) 0.115M 117 +114 1.115 3 =115 M. Standard deviation (see Experiment 8) 0.0283M (147-15)²+(114-115)²+(115-115) ² -0.0283 M 3-1 =.117 M •114 M . =.115 M 43g Hip ARED met NOCH 204. 22gup 1 Cup 409g KHP mal x Imol NaOH Imor KHP 204.22g 419gxHPx mal Timel Noct 204.229 Avat kHP Copyright © 2015 Pearson Education, Inc. x 0200202 Mol ₂014 0.01730L 0.00200 Mag 0.01755 0.00205 met 0.01780 Trial 3 X x 419 38.25 20.45 17.80 -115M 342 Repen Sheet Dutcrmination of the Dissociation Constant of a Weak Acid C. Determination of på, of Unknown Acid Second First determination pH determination pH ml. NaOH ml. NaOH 10.50 nen 2.78 1.50 3.05 5135 - 4.6 21.40 5.14 3.77 23.00 349 4.0x 5.80 7.15 5.6.1 9.10 4.18 5.25 11.35 5.64 125 5.10 12.40 13.70 5.38 14.55 5.83 15.65 5.55 16.60 13.65 5.94 4.42 6.01 10.60 5.03 20.55 6.19 21.50 43.60 5.47 33.50 5.44 251.55 6.20 25.10 11.32 6.82 26,63 11.65 2.80 11. S 10.05 151.90 11.49 10:51 29.75 12.00 10.81 30.00 12.07 31.90 12.19 Volume at equivalence point Volume at one-half equivalence point 25.104 12.SS.L 26.00 13.00 pk, 4.50 pk. 4.60 K. X. 2.5LYD Average K., (show calculations) 32255 (SMONG") "(15) Mat (Garam Buttx 105 + Copyright © 2015 Pearson Education, Inc. 333 443 4.50 14.45 4.66 4.29 4.84 24.00 24.12 24.10 29.90 2.4.8 24.30 to 20 14.90 15.00 25.10 15:50 25.60 25.20 26.10 26.10 Third determination ml NaOH pH 2.81 8.01 4.10 13.05 4.36 13.00 S. 34 S.SC 25.00 26.50 6.63 15.90 4.95 26.10 26.10 10. 10 10.41 25.90 12.95 pk. 4.40 K. 3.98 x 5 Standard deviation of K, 7.37 x6 (( - )" (2.5")-(³)) : (²-²) 3-1 = 7.37x166 Using the volume of base at the equivalence point, its molarity, and the fact that you used 25.00 mL of acid, calculate the concentration of the unknown acid and record this on the report sheet. D. Concentration of Unknown Acid Volume of unknown acid Average molarity of NaOH from above mL of NaOH at equivalence point Molarity of unknown acid Average molarity (show calculations) Trial 1 Trial 2 Standard deviation Laboratory Experim Trial 3 B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Mass of bottle + KHP Mass of bottle Mass of KHP used 4139 14.09g Final buret reading 19.55 Initial buret reading 22,10 mL of NaOH used 13.30 17.55 Molarity of NaOH 117 M 114 M Average molarity (show calculations and standard deviation) 0.115M 117 +114 1.115 3 =115 M. Standard deviation (see Experiment 8) 0.0283M (147-15)²+(114-115)²+(115-115) ² -0.0283 M 3-1 =.117 M •114 M . =.115 M 43g Hip ARED met NOCH 204. 22gup 1 Cup 409g KHP mal x Imol NaOH Imor KHP 204.22g 419gxHPx mal Timel Noct 204.229 Avat kHP Copyright © 2015 Pearson Education, Inc. x 0200202 Mol ₂014 0.01730L 0.00200 Mag 0.01755 0.00205 met 0.01780 Trial 3 X x 419 38.25 20.45 17.80 -115M 342 Repen Sheet Dutcrmination of the Dissociation Constant of a Weak Acid C. Determination of på, of Unknown Acid Second First determination pH determination pH ml. NaOH ml. NaOH 10.50 nen 2.78 1.50 3.05 5135 - 4.6 21.40 5.14 3.77 23.00 349 4.0x 5.80 7.15 5.6.1 9.10 4.18 5.25 11.35 5.64 125 5.10 12.40 13.70 5.38 14.55 5.83 15.65 5.55 16.60 13.65 5.94 4.42 6.01 10.60 5.03 20.55 6.19 21.50 43.60 5.47 33.50 5.44 251.55 6.20 25.10 11.32 6.82 26,63 11.65 2.80 11. S 10.05 151.90 11.49 10:51 29.75 12.00 10.81 30.00 12.07 31.90 12.19 Volume at equivalence point Volume at one-half equivalence point 25.104 12.SS.L 26.00 13.00 pk, 4.50 pk. 4.60 K. X. 2.5LYD Average K., (show calculations) 32255 (SMONG") "(15) Mat (Garam Buttx 105 + Copyright © 2015 Pearson Education, Inc. 333 443 4.50 14.45 4.66 4.29 4.84 24.00 24.12 24.10 29.90 2.4.8 24.30 to 20 14.90 15.00 25.10 15:50 25.60 25.20 26.10 26.10 Third determination ml NaOH pH 2.81 8.01 4.10 13.05 4.36 13.00 S. 34 S.SC 25.00 26.50 6.63 15.90 4.95 26.10 26.10 10. 10 10.41 25.90 12.95 pk. 4.40 K. 3.98 x 5 Standard deviation of K, 7.37 x6 (( - )" (2.5")-(³)) : (²-²) 3-1 = 7.37x166
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This question is based on pH metric titration Initially 25mL of acid is taken Therefore the pH is ... View the full answer
Related Book For
Probability & Statistics for Engineers & Scientists
ISBN: 978-0131877115
8th edition
Authors: Ronald E. Walpole, Raymond H. Myers, Sharon L. Myers, Keying Ye
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