Directions (Q. Nos. 89 to 100) are Assertion- Reason type questions. Each of these questions contains...

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Directions (Q. Nos. 89 to 100) are Assertion- Reason type questions. Each of these questions contains two statements: Statement-1 (Assertion) and Statement-2 (Reason) Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice as given below. (a) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1 (b) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1 (c) Statement1 is true, Statement-2 is false (d) Statement-1 is false, Statement-2 is true 89. Statement-1 If 10 coins are thrown simultaneously, then the probability of appearing exactly four heads is equal to probability of appearing exactly six heads. Statement-2 "C, = "C, either r = s or r + s = n and P(H) = P(T) in a single trial. 90. Statement-1 If A is any event and P(B) = 1, then A and B are independent. Statement-2 P(AB)=P(A)- P(B), if A and B are independent. 91. Statement-1 If A and B be the events in a sample space, such that P(A) = 0.3 and P(B) = 0.2, then P(AB) cannot be found. Statement-2 P(AB) = P(A) - P(AB) 92. Statement-1 Let A and B be two events, such that P(AUB)=P(AB), then P(AB')=P(A' B)=0 Statement-2 Let A and B be two events, such that P(AUB)=P(AB), then P(A) + P(B) = 1 93. A fair die is rolled once. Statement-1 The probability of getting a composite number is is Statement-2 There are three possibilities for the obtained number. (i) The number is prime number. (ii) The number is a composite number and (iii) The number is 1. Hence, probabilities of getting a prime number is 1/13 94. From a well shuffled pack of 52 playing cards, a card is drawn at random. Two events A and B are defined as A: Red card is drawn B: Card drawn is either a Diamond or Heart Statement-1 P(A + B)=P(AB) Statement-2 AC Band BCA 95. Statement-1 The probability that A and B can solve a 1 3 1 problem is - and respectively, then the probability that 2 5 problem will be solved is 6 Statement-2 Above mentioned events are independent events. 96. Statement-1 Out of 21 tickets with numbers 1 to 21, 3 tickets are drawn at random, the chance that the numbers on them 10 133 are in AP is Statement-2 Out of (2n + 1) tickets consecutively numbered three are drawn at random, the chance that the numbers on them are in AP is (4n-10)/(4n-1). 97. Statement-1 If A and B are two events, such that 0 Directions (Q. Nos. 89 to 100) are Assertion- Reason type questions. Each of these questions contains two statements: Statement-1 (Assertion) and Statement-2 (Reason) Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice as given below. (a) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1 (b) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1 (c) Statement1 is true, Statement-2 is false (d) Statement-1 is false, Statement-2 is true 89. Statement-1 If 10 coins are thrown simultaneously, then the probability of appearing exactly four heads is equal to probability of appearing exactly six heads. Statement-2 "C, = "C, either r = s or r + s = n and P(H) = P(T) in a single trial. 90. Statement-1 If A is any event and P(B) = 1, then A and B are independent. Statement-2 P(AB)=P(A)- P(B), if A and B are independent. 91. Statement-1 If A and B be the events in a sample space, such that P(A) = 0.3 and P(B) = 0.2, then P(AB) cannot be found. Statement-2 P(AB) = P(A) - P(AB) 92. Statement-1 Let A and B be two events, such that P(AUB)=P(AB), then P(AB')=P(A' B)=0 Statement-2 Let A and B be two events, such that P(AUB)=P(AB), then P(A) + P(B) = 1 93. A fair die is rolled once. Statement-1 The probability of getting a composite number is is Statement-2 There are three possibilities for the obtained number. (i) The number is prime number. (ii) The number is a composite number and (iii) The number is 1. Hence, probabilities of getting a prime number is 1/13 94. From a well shuffled pack of 52 playing cards, a card is drawn at random. Two events A and B are defined as A: Red card is drawn B: Card drawn is either a Diamond or Heart Statement-1 P(A + B)=P(AB) Statement-2 AC Band BCA 95. Statement-1 The probability that A and B can solve a 1 3 1 problem is - and respectively, then the probability that 2 5 problem will be solved is 6 Statement-2 Above mentioned events are independent events. 96. Statement-1 Out of 21 tickets with numbers 1 to 21, 3 tickets are drawn at random, the chance that the numbers on them 10 133 are in AP is Statement-2 Out of (2n + 1) tickets consecutively numbered three are drawn at random, the chance that the numbers on them are in AP is (4n-10)/(4n-1). 97. Statement-1 If A and B are two events, such that 0

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