During a hike a man weighing $120$ kg was trapped in a hole that was $60$m deep. The only way to get the man out was to hoist him using a rope. Assuming the rope was also $60$ m long and the speed to hoist the man out was constant, how much work was spent lifting the man and the rope if the rope weighed $0\mathrm{.}18$ kg$/$m$.$ 

This is a problem involving work energy or E$=$F$*$D

Remember to account for the acceleration caused by gravity $9\mathrm{.}8$ m$/$s

 

Answer rating: 100% (QA)

The work done to lift the man and the rope out of the hole can be computed using the formula for wor... View the full answer