ENGINEERING ECONOMY (SP/22)) Close Operating cost of asset First cost of asset 5. Summit Metalsis planning...

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ENGINEERING ECONOMY (SP/22)) Close Operating cost of asset First cost of asset 5. Summit Metalsis planning to expand its Wichita, Kansas, manufacturing operation 5 years fromnow at a cost of $10,000,000. If the company plans to deposit money into anaccount each year for 4 years beginning 2 years from now (first deposit is inyear 2) to pay for the expansion, the equation that represents the amount ofthe deposit at 9% per year interest is: De (1 Point) O A = 10,000,000(A/F, 9%, 5) A = 10,000,000(A/F, 9%, 4) A = 10,000,000(A/P, 9%, 4) A = 10,000,000(A/F, 9%, 4) (P/F, 9%, 1) 6. What equal annual amount must be deposited for 10 years in order to provide withdrawals of $200 at the end of the second year, $400 at the end of the third year, $600 at the end of the fourth year, and so on, up to $1,800 at the end of the tenth year? The interest rate is 10% compounded annually. (1 Point) G S ENGINEERING ECONOMY (SP/22)) Close Operating cost of asset First cost of asset 5. Summit Metalsis planning to expand its Wichita, Kansas, manufacturing operation 5 years fromnow at a cost of $10,000,000. If the company plans to deposit money into anaccount each year for 4 years beginning 2 years from now (first deposit is inyear 2) to pay for the expansion, the equation that represents the amount ofthe deposit at 9% per year interest is: De (1 Point) O A = 10,000,000(A/F, 9%, 5) A = 10,000,000(A/F, 9%, 4) A = 10,000,000(A/P, 9%, 4) A = 10,000,000(A/F, 9%, 4) (P/F, 9%, 1) 6. What equal annual amount must be deposited for 10 years in order to provide withdrawals of $200 at the end of the second year, $400 at the end of the third year, $600 at the end of the fourth year, and so on, up to $1,800 at the end of the tenth year? The interest rate is 10% compounded annually. (1 Point) G S

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