Exactly 100 ml of 0.15 M acetic acid (HC2H3O2, Ka=1.8 x 10 -5 ) are titrated with
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Question:
(a) the initial solution (HC2H3O2 )
(b) the point at which 37.5 ml of the base has been added.
(c) equivalence point
(d) after adding 80.0 ml of 0.20 M NaOH.
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