Find on the curve x^2/4-8y^2-25 the closest points to the point (0,0). Find the total derivative...

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Find on the curve x^2/4-8y^2-25 the closest points to the point (0,0). Find the total derivative df/dt: (a) f(x,y)= t^2 (y-4x)^3, where x(t)=ln(6t), and y(t)=4e^(t/2) (b) f(x,y)=ln(xy^2)+e^(x/y)-t, where x(t)-t^2+8 and y(t)-6e^3t. Find on the curve x^2/4-8y^2-25 the closest points to the point (0,0). Find the total derivative df/dt: (a) f(x,y)= t^2 (y-4x)^3, where x(t)=ln(6t), and y(t)=4e^(t/2) (b) f(x,y)=ln(xy^2)+e^(x/y)-t, where x(t)-t^2+8 and y(t)-6e^3t.