Find the average rate of change for the given function over the indicated interval specified by...

 

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Find the average rate of change for the given function over the indicated interval specified by some real number h. Be sure to simplify as much as possible. y=-x² + 6x + 6 on [5,5 + h]. Something to think about for Calculus... Do you see the connection between the average rate of change and the difference quotient? You were asked to find the average rate of change on the interval [5,5 + h]. Once simplified we get the difference quotient for x = 5 which is the foundation for finding the derivative of f(x) at x = 5 in Calculus 1. Find the average rate of change for the given function over the indicated interval specified by some real number h. Be sure to simplify as much as possible. y=-x² + 6x + 6 on [5,5 + h]. Something to think about for Calculus... Do you see the connection between the average rate of change and the difference quotient? You were asked to find the average rate of change on the interval [5,5 + h]. Once simplified we get the difference quotient for x = 5 which is the foundation for finding the derivative of f(x) at x = 5 in Calculus 1. Find the average rate of change for the given function over the indicated interval specified by some real number h. Be sure to simplify as much as possible. y=-x² + 6x + 6 on [5,5 + h]. Something to think about for Calculus... Do you see the connection between the average rate of change and the difference quotient? You were asked to find the average rate of change on the interval [5,5 + h]. Once simplified we get the difference quotient for x = 5 which is the foundation for finding the derivative of f(x) at x = 5 in Calculus 1. Find the average rate of change for the given function over the indicated interval specified by some real number h. Be sure to simplify as much as possible. y=-x² + 6x + 6 on [5,5 + h]. Something to think about for Calculus... Do you see the connection between the average rate of change and the difference quotient? You were asked to find the average rate of change on the interval [5,5 + h]. Once simplified we get the difference quotient for x = 5 which is the foundation for finding the derivative of f(x) at x = 5 in Calculus 1.