Find the distance from the line L1 x = 2t + 2, y = 1-3t, z...

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Find the distance from the line L1 x = 2t + 2, y = 1-3t, z = 3+2t, to the line L2, which is the intersection between plane 2x + 2y -z = 1 and the plane x + 2z = 1. (Hint: One can find the equation of the intersection line by solving the two equations of the planes together with the substitution x = t.) Find the distance from the line L1 x = 2t + 2, y = 1-3t, z = 3+2t, to the line L2, which is the intersection between plane 2x + 2y -z = 1 and the plane x + 2z = 1. (Hint: One can find the equation of the intersection line by solving the two equations of the planes together with the substitution x = t.)

Answer rating: 100% (QA)

To find the distance between the two lines we need to find a point on the first line and a vector th... View the full answer