Find the equilibrium points for the system x'= 10(y - x) y'= 28x - y-xz 8...

   

Transcribed Image Text:

Find the equilibrium points for the system x'= 10(y - x) y'= 28x - y-xz 8 z' = - -z+xy 3 One of the equilibrium points will have all positive coordinates. Those coordinates are: x= y = x = Find the equilibrium points for the system x'= 10(y - x) y'= 28x - y-xz 8 z' = - -z+xy 3 One of the equilibrium points will have all positive coordinates. Those coordinates are: x= y = x =

Answer rating: 100% (QA)

To find the equilibrium points of the system we need to s... View the full answer