. At an intermediate step of the simplex algorithm (for maximization LP), the tableau is: +3x5 2...

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At an intermediate step of the simplex algorithm (for maximization LP), the tableau is: +3x5 2 -201 -4x1 21 2x1 + x2 +13 +4 -25 -3x5 = 15 = 4 = 2 = 6 = (a) (10 points) Find the range for the value of 3 such that optimal solution is unbounded. (b) (8 points) Find the range for the value of 3 such that an optimal solution will be reached in one iteration (one pivot) of simplex method performed on this tableau. (c) (2 points) Write down the optimal solution and optimal value reached in part (b). At an intermediate step of the simplex algorithm (for maximization LP), the tableau is: +3x5 2 -201 -4x1 21 2x1 + x2 +13 +4 -25 -3x5 = 15 = 4 = 2 = 6 = (a) (10 points) Find the range for the value of 3 such that optimal solution is unbounded. (b) (8 points) Find the range for the value of 3 such that an optimal solution will be reached in one iteration (one pivot) of simplex method performed on this tableau. (c) (2 points) Write down the optimal solution and optimal value reached in part (b).

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a 10 points Find the range for the value of such that optimal solution is unb ounded ANS WER The ran... View the full answer