Find the specific heat of the unknown in J/kg .o C using Table 2 below to help.
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Question:
Find the specific heat of the unknown in J/kg.oC using Table 2 below to help. Note that your mass measurements were in grams and not kilograms, so you will have to change your final answer to reflect kilograms.
Variable | Observation |
Mass of cup in grams | 31.2 |
Mass of cup and water in grams | 171.1 |
Mass of unknown material in grams | 181 |
Initial temperature of the unknown material in oC. | 100 |
Initial temperature of the water in oC. | 12 |
Final temperature of the unknown material and the water in oC. | 28.5 |
Show your calculation/work for the mass of water:
Show your calculation/work for the DT for water.
Show your calculation/work the heat gained by the water.
Show your calculation/work for the DT for the unknown.
Show you calculation/work for the specific heat of the unknown in J/g,oC
100c*4.184*171.1= 71588.2
Variable | Calculation Result |
Mass of water in g | |
Specific heat of water J/g,oC | 4.186 |
DT for water (Tf - Ti) | |
Heat Gained by the Water in J | |
Heat Lost by the Metal in J | |
Mass of unknown in g | |
DT for unknown | |
Specific heat of unknown J/g,oC | |
Specific heat of unknown J/kg,oC |
Related Book For
Applied Physics
ISBN: 978-0132109277
10th Edition
Authors: Dale ewen, Neill schurter, P. erik gundersen
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