For x [n] = x[n-1] and x2[n] = x[n-2], it can be shown that: 1. X(Z)...

 

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For x₁ [n] = x[n-1] and x2[n] = x[n-2], it can be shown that: 1. X₁(Z) = x[-1]+ Z-¹X(Z) and 2. X₂(Z) = x[-2] + x[-1] Z-¹ + Z-2X(Z). Using these expressions, find the first six terms of h[n] for a processor with difference equation: y[n] -0.2y[n-1] +0.48y[n-2] + x[n] for (i) zero initial (auxilliary) conditions and (ii) y[-1] = -1.25, y[-2] = -0.52083 Explain the physical effect on the non-zero initial conditions (ii) above h[n]. For x₁ [n] = x[n-1] and x2[n] = x[n-2], it can be shown that: 1. X₁(Z) = x[-1]+ Z-¹X(Z) and 2. X₂(Z) = x[-2] + x[-1] Z-¹ + Z-2X(Z). Using these expressions, find the first six terms of h[n] for a processor with difference equation: y[n] -0.2y[n-1] +0.48y[n-2] + x[n] for (i) zero initial (auxilliary) conditions and (ii) y[-1] = -1.25, y[-2] = -0.52083 Explain the physical effect on the non-zero initial conditions (ii) above h[n].

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To find the first six terms of hn for the processor with the given difference equation we need to co... View the full answer