From a great height from the surface of the Earth, a stone of mass m 2 kg is propelled downward with an intial speed of 1 0 0 0 m sec In addition to gravity ( 9 8 m sec ) , air resistance is acting on the stone with a force that is equal to twice the speed of its stone a Find a formula for the velo...

a To find a formula for the velocity of the stone we need to consider the forces acting on it The two main forces are gravity and air resistance Lets ...

From a great height from the surface of the Earth, a stone of mass m = 2

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Question:

From a great height from the surface of the Earth, a stone of mass m

= 2

kg is propelled downward with an intial speed of

1000

/

sec

.

In addition to gravity

(9.8

/

sec

),

air resistance is acting on the stone with a force that is equal to twice the speed of its stone. a

.

Find a formula for the velocity of the stone. b

.

Find the terminal velocity of the stone. c

.

After how much time does the stone attain

90 %

of its maximum velocity? d

.

When it reaches the velocity in part b

,

how far has it dropped? e

.

Repeat part a with the assumption that the air resistance is

0.01

^2 .

Related Book For answer-question

A First Course in Differential Equations with Modeling Applications

ISBN: 978-1305965720

11th edition

Authors: Dennis G. Zill

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Posted Date: Apr 06, 2024 07:46 PM

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From a great height from the surface of the Earth, a stone of mass m = 2

Question:

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a To find a formula for the velocity of the stone we need to consider the forces acting on it The two main forces are gravity and air resistance Lets ... View the full answer

A First Course in Differential Equations with Modeling Applications

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