From the top of a cliff, a person throws a stone straight downward. The initial speed...

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From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.4 m/s. (a) What is the acceleration (magnitude in m/s and direction) of the stone while it moves downward, after leaving the person's hand? magnitude X Ignoring air resistance, the acceleration of any object in free fall near the earth's surface is the same, regardless of speed. m/s downward direction Is the stone's speed increasing or decreasing? O increasing O decreasing (b) After 0.48 s, how far (in m) beneath the top of the cliff is the stone? (Give just the distance fallen, that is, a magnitude.) X Be careful of signs. If the downward direction is negative, and the initial velocity and acceleration are both downward, what are their algebraic signs? Think about what information you are given, and which constant acceleration relation will allow you to find the distance. m From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.4 m/s. (a) What is the acceleration (magnitude in m/s and direction) of the stone while it moves downward, after leaving the person's hand? magnitude X Ignoring air resistance, the acceleration of any object in free fall near the earth's surface is the same, regardless of speed. m/s downward direction Is the stone's speed increasing or decreasing? O increasing O decreasing (b) After 0.48 s, how far (in m) beneath the top of the cliff is the stone? (Give just the distance fallen, that is, a magnitude.) X Be careful of signs. If the downward direction is negative, and the initial velocity and acceleration are both downward, what are their algebraic signs? Think about what information you are given, and which constant acceleration relation will allow you to find the distance. m

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a What is the acceleration magnitude in ms and direction of the stone while it moves d... View the full answer