Given: String[] a = {a, b, c, d, e, f, g}; String[][] m = new String[3][3];...

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Given: String[] a = {"a", "b", "c", "d", "e", "f", "g"}; String[][] m = new String[3][3]; Write code to create: a f d b e g You may not use direct assignment (m[0][0] = a[0]) for all 8 positions. You are allowed only 1 set of nested loops and you must use the looping values (i.e. m[row][col] = a[row-col-x];)) x would be a variable you create if you so desire. You are only allowed to use one set of nested loops. You can create a separate method to print the matrix to test. public static int rearrange() Given: String[] a = {"a", "b", "c", "d", "e", "f", "g"}; String[][] m = new String[3][3]; Write code to create: a f d b e g You may not use direct assignment (m[0][0] = a[0]) for all 8 positions. You are allowed only 1 set of nested loops and you must use the looping values (i.e. m[row][col] = a[row-col-x];)) x would be a variable you create if you so desire. You are only allowed to use one set of nested loops. You can create a separate method to print the matrix to test. public static int rearrange()

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Here is the code snippet that rearranges the values from the array a into the 3x3 array m using on... View the full answer