Given that the equation for the rate of heat transfer (6) through a solid by conduction...
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Given that the equation for the rate of heat transfer (6) through a solid by conduction is o = kAVT measured in Js- or W where k is the thermal conductivity of the material (WK-m-) A is the surface area (m) VT is the temperature gradient (Km-) Calculate the heat that will pass through a wall that measures 4.5m by 5.5m and has a thickness of 0.4m given that the wall is made from refractory material whose thermal conductivity is 1.5Wm-K-. The inside temperature of the wall is 795K (522 C) and the outside surface is at 303K (30C). Give your answer to the nearest kW Heat flow = 18.55 kW Given that the equation for the rate of heat transfer (6) through a solid by conduction is o = kAVT measured in Js- or W where k is the thermal conductivity of the material (WK-m-) A is the surface area (m) VT is the temperature gradient (Km-) Calculate the heat that will pass through a wall that measures 4.5m by 5.5m and has a thickness of 0.4m given that the wall is made from refractory material whose thermal conductivity is 1.5Wm-K-. The inside temperature of the wall is 795K (522 C) and the outside surface is at 303K (30C). Give your answer to the nearest kW Heat flow = 18.55 kW
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Related Book For
Fundamentals of Heat and Mass Transfer
ISBN: 978-0471457282
6th Edition
Authors: Incropera, Dewitt, Bergman, Lavine
Posted Date:
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