Given the attached reactor coolant pump characteristic curve and the data in the notes, find the operating point on the pump curve for a three loop plant by calculating and plotting the total (friction and form) losses as a function of flow on the pump curve. The operating point is the intersection of the system pressure curve from your calculations and the total pump head curve. The fluid is at 2250 psia, and 554 F such that the density is 46.55 lbm/ft3 and the viscosity is 0.229 lbm/ft-hr. Data: The steam generator has 3388 tubes each with ID of 0.775 inches and the average tube length is 70 feet The cold leg is 27 inches in diameter The hot leg and crossover leg are 29.5 inches in diameter. The cold leg is 10 diameters long and has one 45 degree elbow The hot leg is 10 diameters long and has one 45 degree elbow The cross over leg is 20 diameters long and has three 90 degree elbows There are contraction and expansion losses at the steam generator inlet and exit, assume that the steam generator plenum area is 3 times the tube bundle area. All elbows are short radii For 45 degree elbows, L/De = 15 For 90 degree elbows, L/De = 35 Use below listed flow rates and vessel pressure drops for the calculations: Q = 92000 GPM per loop and Vessel ΔP = 34.28 psia Q = 95000 GPM per loop and Vessel ΔP = 35.28 psia Q = 104500 GPM per loop and Vessel ΔP = 43.51 psia The pump head is given as: Please see picture 1 Plot the calculated operating curve on the pump curve and discuss.

   

Transcribed Image Text:

AP Head ΔΡ, Loop (friction + form).144 Р g 8c (ft) AP Head ΔΡ, Loop (friction + form).144 Р g 8c (ft)

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Calculation of Total Friction and Form Losses The total friction and form losses for each loop can b... View the full answer