Given the following: #includ int a[] {4,6}, i = 0, y =3, z=1; void f(int x){...

 

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Given the following: #includ int a[] {4,6}, i = 0, y =3, z=1; void f(int x){ } int z = 2; 9 0); x = x+y; Z = Z+X; i++; return x+a[i]+y; void g(){ z += 3; y=a[i] +z; } void main(){ } printf("%d", y+f(a[i]) - y); State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right. Given the following: #includ int a[] {4,6}, i = 0, y =3, z=1; void f(int x){ } int z = 2; 9 0); x = x+y; Z = Z+X; i++; return x+a[i]+y; void g(){ z += 3; y=a[i] +z; } void main(){ } printf("%d", y+f(a[i]) - y); State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right.

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Lets analyze the code based on the given Cases A Call by reference dynamic scoping operands are eval... View the full answer