.How many address lines are necessary to address (i) Two kilobytes (1024 x 2 = 2048...

 

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.How many address lines are necessary to address (i) Two kilobytes (1024 x 2 = 2048 bytes), (ii) Four kilobytes (1024 x 4= 4096 bytes), and (iii) Eight kilobytes (1024 x 8 = 8192 bytes) of memories? .How many address lines are necessary to address (i) Two kilobytes (1024 x 2 = 2048 bytes), (ii) Four kilobytes (1024 x 4= 4096 bytes), and (iii) Eight kilobytes (1024 x 8 = 8192 bytes) of memories?

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