If a cannonball is shot directly upward with a velocity of 288 ft per second, its...

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If a cannonball is shot directly upward with a velocity of 288 ft per second, its height above the ground after t seconds is given by s(t)=2881-1612 Find the velocity and the acceleration after t seconds What is the maximum height the cannonball reaches? When does it hit the ground? The velocity after t seconds is v(t) = ft/sec. The acceleration after t seconds is a(t)= ft/sec The cannonball reaches a maximum height of The cannonball hits the ground after t= sec ft. If a cannonball is shot directly upward with a velocity of 288 ft per second, its height above the ground after t seconds is given by s(t)=2881-1612 Find the velocity and the acceleration after t seconds What is the maximum height the cannonball reaches? When does it hit the ground? The velocity after t seconds is v(t) = ft/sec. The acceleration after t seconds is a(t)= ft/sec The cannonball reaches a maximum height of The cannonball hits the ground after t= sec ft.

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A physics problem Velocity after 1 second The velocity function is given by vt dsdt 288t 16 To find ... View the full answer