If a solution containing 84.363g of mercury(II) Chlorate isallowed to react completely with a solution containing 14.334g
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Question:
If a solution containing 84.363g of mercury(II) Chlorate isallowed to react completely with a solution containing 14.334g ofsodium sulfide, how many grams of solid precipitate will be formed?How many grams of the reactant in excess will remain after thereaction?
Expert Answer:
In this problem mercuryII sulfide is the precipitate based on known solubility rules for ionic compo... View the full answer
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